Belt Conveyor Power and Torque Calculator

Size the drive for a unit-handling belt conveyor: belt pull, pulley torque and speed, motor power, IEC motor size and gearbox ratio. Results update as you type.

Parameters

Conveyor
kg
kg
mm
m
deg
Drive
Drive type
0–1
×
Basic mode assumes ideal conditions
  • 100% efficient gearbox
  • Chain drive: 1:1 sprockets, 100% efficient chain
  • Service factor 1.0, belt mass 0 kg

Real drives need more power. Use Advanced for efficiencies, sprocket ratio and a service factor before selecting a motor.

Side view

Side view of the belt conveyor with drive at the head pulley

Results

OK
Recommended motor – Next IEC size
Gearbox ratio – 4 pole, 1430 rpm
Output torque – At pulley shaft
Output speed – At pulley shaft
Belt pull F
–
Power at pulley P
–
Pulley torque T
–
Required motor power
–
Pulley speed n
–
Power × service factor
–
Belt speed
–
Total moving mass
–
Lift height L·sinθ
–

Calculation steps

g = 9.81 m/s² · D in m · v in m/min
QuantityFormulaWith your valuesResult

How belt pull is calculated

The drive has to overcome two forces: friction between the belt and the bed it slides or rolls on, and gravity pulling the load back down an incline. For a total moving mass m on a conveyor inclined at angle θ, the normal force on the bed is m·g·cosθ and the component of weight along the belt is m·g·sinθ, so the belt pull is:

F = m × g × (μ × cosθ + sinθ)

Torque at the drive pulley is belt pull times pulley radius, and power is force times speed. The motor also has to cover the losses in the gearbox and, if fitted, the chain drive, so the required power is divided by those efficiencies. A service factor is applied and the result is rounded up to the next standard IEC motor size.

This simplified method suits light to medium unit-handling conveyors (boxes, totes, cartons). It does not separately include belt bending, bearing losses, scrapers, acceleration or return strand friction. For bulk material or long, heavy conveyors use a full CEMA or ISO 5048 / DIN 22101 calculation.

What each input means

Basic / Advanced
Basic asks only for what changes the answer most and assumes ideal conditions (no drive losses, service factor 1.0). Both modes let you pick direct or chain drive (Basic assumes 1:1 sprockets). Advanced adds sprocket teeth, efficiencies, service factor, belt mass and length.
Maximum load, belt mass
Total product mass on the belt at the worst moment, plus the carrying belt if you want to include it.
Pulley diameter
Outside diameter of the drive pulley including lagging. Larger pulleys need more torque and turn slower.
Belt speed
Required belt speed, in m/min or m/s. The calculation converts to m/min internally.
Incline angle
Belt angle above horizontal. Above about 18° smooth belts can let products slide back.
Friction coefficient μ
Slider beds have far higher friction than roller beds. Use your belt supplier's value if you have one.
Drive type, sprockets
Direct: shaft-mounted gearmotor on the pulley. Chain: driven ÷ driver teeth multiplies torque and divides speed; roller chain is about 0.95 to 0.98 efficient.
Efficiencies, service factor
Helical gearboxes are about 0.94 to 0.97, worm gearboxes 0.50 to 0.90. A service factor of 1.25 to 1.5 suits steady conveyor duty.