Chain Conveyor Power and Torque Calculator
Size the drive for a drag or slat chain conveyor running on wear strips: carry and return side chain pull, accumulation, sprocket torque and speed, motor power, IEC motor size, motor poles and gearbox ratio.
Generated ·
Side view
Results
- Gearbox ratio needed
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- Motor torque required
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- Rated torque
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- Utilisation
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- Total chain pull F
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- Power at sprocket
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- Sprocket torque T
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- Required motor power
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- Sprocket speed n
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- Power × service factor
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- Chain speed
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- Sprocket pitch diameter
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- Carry side pull
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- Return side pull
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- Accumulation pull
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- Lift height L·sinθ
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Motor comparison
| Motor | Speed (rpm) | Gearbox ratio | Motor torque | IEC motor | Status |
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Calculation steps
| Quantity | Formula | With your values | Result |
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Worked example
Default inputs in Advanced mode: 12 tooth sprocket on 25.4 mm pitch chain, 500 kg load, chain 2.6 kg/m per strand × 2 strands × 5 m, UHMW wear strip μ = 0.15, flat (0°), 10 m/min, no accumulation, direct drive, gearbox efficiency 0.90, service factor 1.5, 50 Hz supply, Auto motor.
- Pitch diameter = 25.4 / sin(180° / 12) = 98.14 mm; chain mass = 2.6 × 2 × 5 = 26 kg
- Carry side = (500 + 26) × 9.81 × 0.15 = 774.0 N; return side = 26 × 9.81 × 0.15 = 38.3 N; total chain pull 812.3 N
- Sprocket torque T = 812.3 × 0.0981 / 2 = 39.9 Nm
- Sprocket speed n = 10 / (π × 0.0981) = 32.4 rpm
- Power at sprocket P = 812.3 × 10 / 60000 = 0.135 kW
- Required motor power = 0.135 / 0.90 = 0.150 kW; × service factor 1.5 = 0.226 kW → 0.25 kW IEC motor
- Gearbox ratio (Auto: 4 pole, 1440 rpm at 50 Hz) = 1440 / 32.4 = 44.4 : 1, motor shaft torque = 0.150 × 9550 / 1440 = 1.00 Nm
In Basic mode (ideal conditions: chain mass ignored, no accumulation, 100% efficient drive, service factor 1.0) the same load, sprocket, speed and μ need 0.123 kW, so a 0.18 kW motor.
How chain conveyor pull is calculated
A drag or slat chain slides on wear strips, so the pull comes from sliding friction on both the loaded carry side and the empty return side, plus gravity on an incline. With chain mass w per strand per metre, s strands and length L:
Fcarry = (load + w × s × L) × g × (μ × cosθ + sinθ)
Freturn = w × s × L × g × (μ × cosθ − sinθ), not less than 0
On a steep incline the returning chain runs downhill and helps the drive, so the return side pull is limited to zero. If product is held back while the chain keeps running (accumulation), the chain also slides under the product, adding load × g × μp. The total is converted to torque at the drive sprocket pitch diameter, where the pitch diameter of a sprocket is p / sin(180°/z).
This simplified method ignores sprocket and bearing losses, chain articulation and catenary tension. Check the result against the chain's allowable working load per strand with your chain supplier.
What each input means
- Basic / Advanced
- Basic assumes ideal conditions: chain mass ignored, no accumulation, 100% efficient drive, service factor 1.0. Advanced adds chain mass, strands, length, accumulation, efficiencies and service factor.
- Drive sprocket
- Enter the pitch diameter directly, or the number of teeth and the chain pitch and the calculator works out the pitch diameter.
- Maximum load
- Total product mass on the chain at the worst moment.
- Chain mass, strands
- Mass of one strand per metre (from the chain catalogue) and how many strands run side by side.
- Wear strip friction μ
- Chain sliding on UHMW is about 0.15, nylon about 0.20 and steel about 0.30 when lubricated or clean.
- Accumulation
- Select Yes when product can be stopped while the chain keeps running. μp is the friction between product and chain.
- Incline angle
- Chain angle above horizontal. Steep inclines may need flights or pushers to stop product sliding back.
- Efficiencies, service factor
- Helical gearboxes are about 0.94 to 0.97, worm gearboxes 0.50 to 0.90. A service factor of 1.25 to 1.5 suits steady duty.
- Motor poles, Auto
- Auto picks a 4 pole motor (1440 rpm at 50 Hz, 1740 rpm at 60 Hz) when the gearbox ratio is between 5 and 150. If the ratio would be above 150 it steps to a 6 or 8 pole motor. A ratio below 5 needs a larger drive diameter or a low-ratio gearbox, because a slower motor would lower the ratio further. 2 pole motors are never picked automatically.
- Custom motor
- Enter the nameplate speed and power of an existing motor. It passes when its rated power covers the required power times the service factor, is marginal when it only covers the required power, and is undersized below that.
- VSD
- With a variable speed drive the conveyor speed changes in proportion to frequency. Below about 25 Hz a standard motor may need forced cooling at full torque.
Disclaimer: results are estimates for preliminary sizing of unit-handling conveyors using simplified formulas. Always verify motor, gearbox and chain selections with the manufacturer's data. Generated by ConvCalcs.
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