Bulk Material Belt Conveyor Calculator (ISO 5048)
Size a troughed belt conveyor for sand, gravel, coal, ore, grain and other bulk materials: capacity and belt fill, effective tension, power, motor and gearbox, belt tensions, take-up and belt rating. Scope: horizontal and inclined conveyors only (no declines), single head drive, 3 equal roll troughing idlers or a flat belt.
Generated ·
Side view
Cross-section
Results
- Gearbox ratio needed
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- Motor torque required
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- Rated torque
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- Utilisation
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- Max capacity Qmax
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- Belt fill
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- Cross-section S
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- Incline δ
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- Material load mG
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- Friction resistance Ffr
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- Lift resistance Fst
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- Effective tension FU
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- Power at pulley P
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- Required motor power
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- Power × service factor
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- Pulley speed n
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- Pulley torque T
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- T1 running
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- T1 at start-up
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- T2 slack side
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- T2 governed by
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- Tail tension
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- Gravity take-up mass
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- Belt rating needed
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- Suggested belt (textile EP)
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- Belt speed
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Estimates only. See Disclaimer.
Motor comparison
| Motor | Speed (rpm) | Gearbox ratio | Motor torque | IEC motor | Status |
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Calculation steps
| Quantity | Formula | With your values | Result |
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Worked example
Default inputs: coal (ρ 0.85 t/m³, θ 20°), Q = 300 t/h, B = 800 mm, λ = 35°, v = 2.5 m/s, L = 100 m, H = 10 m, default masses and spacings, f = 0.020, 500 mm rubber lagged pulley (μ 0.35), α = 210°, kA 1.5, 1 % sag, belt safety factor 10, gearbox efficiency 0.95, service factor 1.1, 4 pole motor at 50 Hz.
- Usable width b = 0.9 × 0.8 − 0.05 = 0.670 m; S1 = 0.02226 m², S2 = 0.04687 m², S = 0.06914 m²
- Incline δ = asin(10 / 100) = 5.74°; k1 = 0.9563, k = 0.9859
- Qmax = 3600 × 0.06914 × 2.5 × 0.85 × 0.9859 = 521 t/h, belt fill 57.5 %
- mG = 300 / (3.6 × 2.5) = 33.33 kg/m, mB = 9.6 kg/m, mR = 12.17 kg/m, C = 1.78
- Ffr = 2,250 N, Fst = 3,270 N, FU = 5,520 N
- P = 13.80 kW at the pulley, 14.53 kW required motor power → 18.5 kW motor; pulley 95.5 rpm and 1,380 Nm; gearbox ratio about 15.1 : 1
- T2: slip 3,177 N, carry sag 7,013 N (Tsag 6,318 N, Fret -695 N), return sag 3,532 N → T2 = 7,013 N (carry side sag)
- T1 = 12,533 N running, 15,294 N at start-up; tail tension 6,318 N; take-up about 1,430 kg
- Belt rating 157 N/mm → EP250; backstop required because Fst is more than half of Ffr
Basic mode uses these same recommended defaults, so it gives the same result. Use Advanced to enter your own idler, belt and drive data.
How the bulk conveyor is calculated
Capacity and belt fill
The material sits in the trough formed by three equal idler rolls. ISO 5048 splits its cross-section into a trough part S2 (below the line joining the material edges) and a surcharge part S1 (a heap whose slope is the surcharge angle θ). Only a usable width b = 0.9 B − 0.05 is loaded, to keep the edges clean.
Qmax = 3600 × S × v × ρ × k
On an incline the heap flattens, so the slope factor k reduces the surcharge part. If the incline reaches the surcharge angle, the surcharge part is lost. Belt fill is the required capacity as a share of Qmax; aim for 85 % or less to avoid spillage.
What C and f mean
The friction factor f covers the main resistances along the conveyor: idler rotation, belt flexing over the idlers and the material being kneaded as it passes each idler. The length coefficient C adds the secondary resistances that do not grow with length, such as loading the material, belt cleaners and pulley bearings, so C is large for short conveyors and close to 1 for long ones.
FU = C f L g [mR + (2 mB + mG) cosδ] + H g mG
Why T2 is set by slip or sag
The drive pulley can only pass the effective tension to the belt if the slack side has enough tension, by Euler's belt friction: T1 / T2 ≤ eμα. At start-up the drive pulls kA × FU, so T2 must stop slip then. The belt must also not sag too much between idlers, mostly at the tail where the tension is lowest. T2 is the largest of these needs, and the take-up applies it.
When a backstop is needed
On an incline the material wants to run back when the conveyor stops. If the lift resistance is more than about half of the friction resistance, friction alone will not hold the loaded belt, so a backstop (holdback) is needed on the drive.
This is a preliminary sizing method. Long, high powered, curved or declined conveyors need a full ISO 5048 or CEMA design with dynamic start and stop analysis. Confirm belt, idler and pulley selections with the suppliers.
What each input means
- Basic / Advanced
- Basic uses the recommended defaults: f = 0.020, start-up factor 1.5, 1 % sag, belt safety factor 10, gearbox efficiency 0.95, service factor 1.1, and belt and idler masses estimated from the belt width. Advanced lets you enter your own values.
- Material values
- Bulk density, surcharge angle, maximum incline and maximum belt speed are typical values. Confirm them for your material, because moisture and lump size change them.
- Belt width, trough angle, speed
- A wider belt, a deeper trough or a faster belt carries more. Narrow belts should not run faster than about 2 m/s.
- Length and lift
- L is measured along the belt between pulley centres. H is the lift from tail to head; it must be 0 or positive because declines are outside the scope of this calculator.
- Friction factor f
- 0.017 for a well aligned and maintained conveyor, 0.020 for normal conditions, 0.023 to 0.030 for poor alignment, cold or dirty conditions.
- Start-up factor kA
- The peak drive force at start-up compared with running. VFD or soft starter 1.2 to 1.3, fluid coupling 1.3 to 1.5, direct on line (DOL) 1.8 to 2.2.
- Pulley friction μ and wrap α
- Lagging and a larger wrap angle let the pulley drive with less slack side tension. Rubber lagged 0.35, ceramic 0.40, bare steel 0.25 dry or 0.10 wet.
- Belt safety factor and rating
- The belt rating needed is T1 × S / B. A safety factor of about 10 suits textile EP belts; the belt supplier may need a heavier carcass for impact, load support and troughing.
- Lump size
- The belt width should be at least 3 times the largest lump for mixed material, or 5 times if all lumps are the same size.
- Motor poles, Auto
- Auto picks a 4 pole motor (1440 rpm at 50 Hz, 1740 rpm at 60 Hz) when the gearbox ratio is between 5 and 150. If the ratio would be above 150 it steps to a 6 or 8 pole motor. A ratio below 5 needs a larger drive diameter or a low-ratio gearbox, because a slower motor would lower the ratio further. 2 pole motors are never picked automatically.
- Custom motor
- Enter the nameplate speed and power of an existing motor. It passes when its rated power covers the required power times the service factor, is marginal when it only covers the required power, and is undersized below that.
- Motor supply: DOL or VFD
- DOL (direct on line) runs the motor straight from the supply at full speed. A VFD (variable frequency drive, also called an inverter or VSD) changes the motor speed by changing the frequency, so the conveyor speed changes in proportion; the design frequency is where it runs at the set speed. Self-cooled motors need derating below about 25 Hz. The 87 Hz switch (104 Hz at 60 Hz) runs a 230/400 V motor in delta for about 1.73 times the power, so a smaller motor and a higher gearbox ratio.
- Abbreviations
- IEC: International Electrotechnical Commission, whose standard motor sizes (0.18 to 22 kW here) are used for the recommended motor. DOL: direct on line. VFD: variable frequency drive. PWM: pulse width modulation, the fast voltage pulses a VFD uses to build its output. SF: service factor. μ: friction or rolling resistance coefficient. rpm: revolutions per minute.
Disclaimer: results are estimates for preliminary sizing of unit-handling conveyors using simplified formulas. Always verify motor, gearbox and chain selections with the manufacturer's data. Generated by ConvCalcs.
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